J.R. S. answered 04/01/19
Tutor
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(145)
Ph.D. University Professor with 10+ years Tutoring Experience
V1M1 = V2M2
(x ml)(0.746 M) = (680 ml)(0.131 M)
Solve for x to get your answer.
Ellie R.
asked 04/01/19what volume of .746 M manganese(iv) chloride is needed to make 680. ml solution of this salt with a chloride concentration of .131 M?
J.R. S. answered 04/01/19
Ph.D. University Professor with 10+ years Tutoring Experience
V1M1 = V2M2
(x ml)(0.746 M) = (680 ml)(0.131 M)
Solve for x to get your answer.
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