J.R. S. answered 03/30/19
Ph.D. University Professor with 10+ years Tutoring Experience
CH3COOH + NaOH ==> CH3COONa + H2O
mmoles NaOH used = 5.28 ml x 0.1 mmol/ml = 0.528 mmoles
mmoles CH3COOH = 0.528 mmoles (1:1 mol ratio)
0.528 mmol/15 ml x 100 ml = 3.52 mmol CH3COOH/100 ml
3.52 mmol/100 ml x 60 mg/mmol x g/1000 mg = 0.2 g/100 ml
Not legally vinegar.
J.R. S.
03/30/19
Mailan D.
Thank you!03/30/19