What pressure (in kPa) is exerted by 0.622 moles of gas contained in a 9.1mL vessel at 16°C

Answer 1

16 deg C + 273 = 289 K

PV = nRT

(P)(9.1 L) = (0.622 mol)0.0821 Latm/Kmol)(289K)

Solve for P and tgen convert to kPa by multiplying by 101.325 kPa/atm