Let x be the normal distribution with μ=52.1 and σ=7.5. What is the x-value representing the twelfth percentile, P12. (Round to the nearest hundredth.):

Answer 1

It's about 43.28

You find Prob(z < k) = 0.12 doing a reverse lookup in the table

It's about k=-1.176

Then you do x = k * 7.5 + 52.1

Plugging in the value for k gives you about 43.28