I do not understand my chemistry homework

Question

We had to create a mixture that has 97% zinc and 3% copper. We also had to demonstrate how to isolate the copper using HCl. We also need to show, using calculations and balanced reactions why HCl is used and the amount of zinc chloride (in moles then in grams) that is produced

Answer 1

To make 100 g of the mixture, mix 97 g Zn with 3 g Cu. For less than 100 g, take proportionately less of each metal (for 10 g mixture use 9.7 g Zn + 0.3 g Cu).

Zn will react with HCl but Cu will not (see the activity series of metals)

Zn(s) + 2HCl(aq) ==> ZnCl2(aq) + H2(g)

Cu(s) + HCl ==> no reaction

The mass of ZnCl2 produced depends on the grams of Zn you start with. The 97% doesn't really help unless we know the mass of the mixture that was used.