J.R. S. answered 03/24/19
Ph.D. University Professor with 10+ years Tutoring Experience
Replace 82.37 g Fe with 63.77 g Fe
Fe2O3(s) + 2Al(s) ==> 2Fe(l) + Al2O3(s)
Find moles of Fe and then from the stoichiometry, find moles of Fe2O3 needed. Finally, convert moles to g.
(1) moles Fe = 82.37 g Fe x 1 mol Fe/55.85 g = 1.4748 moles Fe
(2) moles Fe2O3 needed = 1.4748 mol Fe x 1 mol Fe2O3/2 mol Fe = 0.7374 moles Fe2O3 needed
(3) g Fe2O3 needed = 0.7374 mol Fe2O3 x 159.7 g/mol = 79.85 g Fe2O3 needed