A 6.0 g sample of carbon is burned to produce carbon dioxide. The yield from the reaction is 60%. How much carbon dioxide was actually produced?

Question

 a

13 g

 b

44 g

 c

3.6 g

 d

22 g

Answer 1

C + O2 → CO2

6.0 g C x (1 mol C/ 12.01 g C) x (1 mol CO2/1 mol C) x (44.01 g CO2/1 mol CO2) = 21.99 g CO2 This is the theoretical yield. 22 when sig figged...

%Y = AY/TY

AY = (%Y)(TY) = (.60)(21.99g) = 13.19 g CO2 actual yield. 13 when sig figged...