The given molar mass for silver is 108 g/mol and for nitric acid is 63 g/mol. Which of the following determines teh minimum volume in (mL) of 8.0 M HNO3 needed to dissolve 2.0 g of silver metal?

Question

how would i solve this????

Answer 1

The balance equation:

Ag + 2HNO3 = AgNO3 + NO2 + H2O

The ratio = dissolve 1mol Ag will consum 2mol HNO3

2.0g Ag × 1mol Ag/108g Ag × 2mol HNO3/1mol Ag = 0.037mole HNO3

0.037 mole/ 8.0 mol/L × 1000ml/1L = 4.6 ml

 We need minimum volume 4.6mL of 8.0 M HNO3 needed to dissolve 2.0 g of silver metal.