The area of rectangle A is 3000

The width of rectangle B is 40 (80% of 50)

so the length of rectangle B can be calculated as 40 x l = 3000

l= 75 which is 25% larger than 60 (15/60 = .25)

Imari G.

asked • 03/22/19Rectangle A has a length of 60 inches and a width of 50 inches. Rectangle A has the same area as rectangle B, but has different dimensions. The width of rectangle B is 20% shorter than the width of rectangle A as shown.

Which percent represents how much longer the length of Rectangle B must be to maintain the same area as Rectangle A?

Answer Choices

It must be 50% longer than rectangle A.

It must be 20% longer than rectangle A.

It must be 25% longer than rectangle A.

It must be 100% longer than rectangle A.

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The area of rectangle A is 3000

The width of rectangle B is 40 (80% of 50)

so the length of rectangle B can be calculated as 40 x l = 3000

l= 75 which is 25% larger than 60 (15/60 = .25)

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