The standard enthalpy change for the following reaction is 511 kJ at 298 K. SnCl4(l) Sn(s, white) + 2 Cl2(g) What is the standard heat of formation of SnCl4(l)? kJ/mol

Question

The standard enthalpy change for the following reaction is 511 kJ at 298 K.

1. SnCl₄(l) Sn(s, white) + 2 Cl₂(g)

What is the standard heat of formation of SnCl₄(l)?  ____ kJ/mol

Answer 1

SnCl₄(l) Sn(s, white) + 2 Cl₂(g) ∆H = 511 kJ

Sn(s) + 2Cl₂(g) ---> SnCl₄(l) ∆H = -511 kJ