J.R. S. answered 03/22/19
Tutor
5.0
(145)
Ph.D. University Professor with 10+ years Tutoring Experience
CaH2(s) <==> Ca(s) + H2(g) ∆H = 186 kJ
Ca(s) + H2(g) <==> CaH2(s) ∆H = -186 kJ
Madison L.
asked 03/22/19The standard enthalpy change for the following reaction is 186 kJ at 298 K.
What is the standard heat of formation of CaH2(s)? kJ/mol
J.R. S. answered 03/22/19
Ph.D. University Professor with 10+ years Tutoring Experience
CaH2(s) <==> Ca(s) + H2(g) ∆H = 186 kJ
Ca(s) + H2(g) <==> CaH2(s) ∆H = -186 kJ
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.