what is the molarity where 3.21g of CaCl2 is in a 0.5 L solution

Answer 1

molar mass CaCl₂ = 111 g/mole

3.21 g x 1 mol/111 g = 0.0289 moles

molarity = moles/liter

molarity = 0.0289 moles/0.5 liters = 0.0578 M = 0.06 M (to 1 significant figure)