Balance and label the oxidation state of each element in each reaction.

Question

Oxidation: Zn --> Zn2+ + 2e-

Reduction: As2O3 + 12e- + 6H+ --> 2As3- + 3H2O

Reactions:

As2O3 + 6Zn + 6H+ --> 2As3- + 6Zn2+ 3H2O

As2O3 + 6Zn + 6H2SO --> 2AsH3 + 6ZnSO4 + 3H20

Answer 1

Looks like you've already balanced the oxidation-reduction reaction.

As₂O₃ + 6Zn + 6H₂SO₄ --> 2AsH₃ + 6ZnSO4 + 3H₂0

Oxidation states of elements on left side of equation:

As = 3+

O = 2-

Zn = 0

H = 1+

S = 6+

O = 2-

Oxidation states of elements on right side of equation:

As = 3+

H = 1-

Zn = 2+

S = 6+

O = 2-

H = 1+

O = 2-