J.R. S. answered 03/20/19
Ph.D. University Professor with 10+ years Tutoring Experience
I'm sorry I mis-read your question the first time. This is the correct way to solve this problem.
55.5 g CaCl2 x 1 mole CaCl2/111 g = 0.50 moles
(300 g + 55.5)(1 ml/1.05 g) = 355.5/1.05 = 338.6 ml
0.50 moles/338.6 ml x 1000 ml/L = 1.48 mol/L = 1.48 M

J.R. S.
03/20/19
Laura J.
I was struggling for what to do with the density information since last night. Thank you so much!03/20/19