Trigonemetry-Finding heat lost and absorbed

Question

1. You place a bottle containing 1.5 Liters of mineral water at 30*C into a refrigerator to cool to 6*C. 
2. How many kJ of heat are lost by the water?

q=1500 g*C *24*C

This is how far I've gotten and I have no idea how to find the specific heat...

b. How many kJ of heat are absorbed by the refrigerator? (2 points)

For this, I assume I would just type the kilo joules lost by the water..?

Answer 1

This isn't really trigonometry, but here goes anyway...

You must know or be given or look up the specific heat of mineral water. You cannot solve the equation if you have 2 unknowns.

mass of water = 1.5 kg x 1000 g/kg = 1500 g

C for water = 4.184 J/g/deg assuming the mineral water has the same specific heat as pure water

∆T = 24 degrees

q = (1500 g)(4.184 J/g/deg)(24 deg) = 150,624 J = 150.6 kJ of heat lost by the water

Yes, you just type in the kJ lost by the water. So, 150.6 kJ of heat was absorbed by the refrigerator.