Not that I am aware of.
Of course, sin x = ∑x2k+1/(2k+1)! for k=0 to ∞, but I doubt that is what you want.
Also you might want to look up some math history to understand how the ancient Greeks calculated sines.
Start with Ptolemy's theorem!
Not that I am aware of.
Of course, sin x = ∑x2k+1/(2k+1)! for k=0 to ∞, but I doubt that is what you want.
Also you might want to look up some math history to understand how the ancient Greeks calculated sines.
Start with Ptolemy's theorem!
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