How many grams of magnesium chloride can be produced from 2.30 moles of chlorine gas reacting with excess magnesium? Mg (s) + Cl₂ (g) → MgCI₂ (s)

Question

A) 438 g

B) 326 g

C) 219 g

D) 109 g

Answer 1

Mg(s) + Cl₂(g) ==> MgCl₂(s)

2.3 moles Cl₂ x 1 mol MgCl₂/mol Cl₂ x 95.2 g/mol MgCl₂ = 219 g (answer C)