Ben B. answered 11/19/14
Tutor
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Experience Aerospace Engineer with Master's Degree in Physics
Local linealization refers to the rate of change of a function in a small neighborhood of a point. For example, for (a), where you have a function f(x), you want to examine the rate of change of f(x) with respect to a small change in x, as it occurs near the point x=0 and f(x=0). So you want to take the derivative of f(x) with respect to x, and then set x= 0. This rate of change of the function can then be used to approximate values of the funciton for small variations near a point of interest.
If f(x) = ln(1 + x^3), then
df/dx= 2x^2 / (1 + x^3)
so df/dx= 0 near x= 0, and the value of the function in the neighborhood of x=0 will be 0. You can verify this by making a graph of the function.
For part (b), you do the same thing, with the function
f(x)= sin(x)
df/dx = cos(x) = 1 at x=0.
so, sin(0.2)= sin(0) + df/dx (at x=0) * (0.2) = 0.2.
This is the famous small anlge approximation for the sin function where the sin Θ = Θ (approximately).
- Ben