1.11g of calcium chloride is added to water forming 500ml solution. 20ml of this solution is taken and diluted 10folds.Find moles of chloride ions in 2ml of diluted solution

Answer 1

1.11 g CaCl₂ x 1 mole/111 g = 0.01 moles CaCl₂

0.01 moles CaCl₂/500 ml x 2 moles Cl^-/mole CaCl₂ = 4x10^-5 moles Cl^-/ml

Diluted this 10 fold = 4x10^-6 moles Cl^-/ml

In 2 mls you have 4x10^-6 moles Cl^-/ml x 2 ml = 8x10^-6 moles Cl^-