What is the mol fraction of propanol, C3H7OH, in a solution of 65.7g of propanol and 475g of water?

Answer 1

Moles propanol = 65.7 g x 1 mole/60.1 g = 1.09 moles

Moles H2O = 475 g x1 mol/18g = 26.4 moles

mole fraction propanol = 1.09/(1.09 + 26.4) = 0.0396