Nicole H. answered 11/13/14
Tutor
4.9
(172)
Knowledgeable and Motivated Chemistry and Algebra tutor
Ariel,
Let's label the angles a, b and c.
In a triangle, the sum of the angles equals 180: a + b + c = 180 (first equation)
The 3rd angle is 3 more than twice the measure of the second angle: c = 2b + 3 (second equation)
The first angle is 24 more than twice the measure of the third angle: a = 2c + 24 (third equation)
You now have 3 equations and 3 variables:
a + b + c = 180
2b - c = -3
a -2c = 24
Multiply the third equation by -1 and you will get -a + 2c = -24
Add the first and third equation and you will get b + 3c = 156
Multiply the second equation by 3 and you will get 6b - 3c = -9
You now have a system of 2 equations: b + 3c = 156 and 6b - 3c = -9; if you add those 2 equations, you will get 7 b = 147 and therefore b = 21
Substitute the value of b in the original second equation: c = 2(21) + 3 = 42 + 3 = 45
Substitute the value of c in the original third equation: a = 2(45) + 24 = 90 + 24 = 114
If you add a + b + c = 114 + 21 + 45 = 180
Hope it helps