
Lauren H. answered 03/16/19
7 years experience teaching High School Chemistry and Honors Chemistry
T(°C) = (T(°F) - 32) × 5/9
Solve for F:
Tf = Tc(9/5) + 32
Lauren H. answered 03/16/19
7 years experience teaching High School Chemistry and Honors Chemistry
T(°C) = (T(°F) - 32) × 5/9
Solve for F:
Tf = Tc(9/5) + 32
J.R. S. answered 03/14/19
Ph.D. University Professor with 10+ years Tutoring Experience
There are several formulae to do this. Here are just 2. There are others.
F =(C × 9/5) + 32 or (°F - 32) x 5/9 = °C
Ex: 212 degrees F
(212-32) x 5/9 = 180 x 5/9 = 100 degrees C
F = 1.8C + 32 or (F-32)/1.8
Ex: 212 degrees F
(212-32)/1.8 = 180/1.8 = 100 degrees C
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