I need help in algebra

Question

I need help with a math problem in my workbook

 

m^2+4m+4

 

Answer 1

How do we factor m^2+4m+4; the book equation is ax^2+bx+c

I always look at c first. C=4 What are the factors of 4; (2*2) or (4*1).

then there is b= 4, I am looking back at the factors of 4.

This may seem confusing because in this case b=c. We want to know what factors of 4(c) can we add together to get 4(b) which is 2*2 gives us c and 2+2 gives us b.

Then we can start plugging in the numbers we can factor m^2+4m+4 can be factored into (m+2)(m+2) or as Tracey said (m+2)^2.

Then we can take m+2=0, subtract 2 from each side.

m=-2

Answer 2

m^2+4m+4=0

• factors of 4 are (2*2) and (4*1). 2+2= 4 and 2*2=4 so you know 2 is the number you have to use. Replace 4m with 2m+2m.

m^2+2m+2m+4=0

• Group the expression by using parentheses. (make sure to leave the positive sign in the middle)

(m^2+2m)+(2m+4)=0

• factor out m in the first parentheses, and two in the other.

m(m+2)+2(m+2)=0

• when you factor out m you find that you are left with (m+2) in both "spaces". This ensures that you are correct up to this point. Now all you have to do is grab the m and +2 in front of both parentheses and combine them, and then leave one (m+2).

(m+2)(m+2)=0

• now all you have to do is set m+2=0 and you find that you get m=-2 in both expressions.
• to check your answer plug in -2 and you should get 0 on both sides.

 

Answer 3

(m+2)²=0

m=-2