
Amanuel Z. answered 12/28/14
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Lets start by writing a balanced chemical equation for the titration/ neutralization process:
H2C2O4.2H2O + Ba(OH)2 = BaC2O4 + 4H2O
1 mole H2C2O4.2H2O = 1 mole Ba(OH)2 = 126g H2C2O4.2H2O
Equality of mass and volume:
0.896g H2C2O4.2H2O = 0.0382 L Ba(OH)2
Our goal = mol Ba(OH)2/L Ba(OH)2 = Molarity of Ba(OH)2
Now lets set up the given values and calculate the unknown:
1mol Ba(OH)2 0.896 g H2C2O4.2H2O
------------------------------- x ---------------------------- = 0.186 mol/L Ba(OH)2
126 g H2C2O4.2H2O 0.0382 L Ba(OH)2
------------------------------- x ---------------------------- = 0.186 mol/L Ba(OH)2
126 g H2C2O4.2H2O 0.0382 L Ba(OH)2
The molarity of barium hydroxide is 0.186 M.