how many grams of Lead can be released decomposing 22 gram of Lead(IV) oxide?

Answer 1

Pb(IV) oxide is PbO₂

molar mass = 239 g/mol

22 g x 1 mol/239 g = 0.0921 moles PbO₂ = 0.0921 mol Pb

mass Pb = 0.0921 mol x 207 g/mol = 19 g of lead