What mass of carbon dioxide will be formed when a mixture containing 1.93 g of ethylene and 5.92g of oxygen is ignited?

Question

C2H4 + 3O2 -> 2CO2 + 2H2O

Answer 1

C₂H₄ + 3O₂ ==> 2CO₂ + 2H₂O

Find the limiting reactant:

moles ethylene = 1.93 g x 1 mole/28.05 g = 0.06881 moles C₂H₄ = 0.1376 moles CO2 produced

moles O₂ = 5.92 g x 1 mole/32 g = 0.185 moles O₂ = 0.1233 moles CO2 produced

O₂ is limiting

mass CO₂ produced = 0.1233 moles CO₂ x 44 g/mole = 5.43 g CO₂ produced