LA QUIMICA Chemistry help please please with cherry on top

Question

You are asked to make 500.0 mL of a 1.00M SOLUTION OF HCL for a lab. You find some HCL in a cabinet, but the concontration is 12.4 M. How would you dilute the acid to get the 1.00 M solution you need?

Answer 1

Simply use the formula V1M1 = V2M2 where V1 and V2 are volume 1 and volume 2 respectively, and M1 and M2 are molarity 1 and molarity 2, respectively.

(x ml)(12.4 M) = (500.0 ml)(1.00 M)

x = 40.3 mls (to 3 sig. figs.)