13.0 grams of calcium react with 23.6 grams of chlorine. What is the empirical formula, calculated from this data, of calcium chloride?

Question

13.0 grams of calcium react with 23.6 grams of chlorine. What is the empirical formula, calculated from this data, of calcium chloride?

Answer 1

Moles Ca = 13.0 g x 1 mol/40.1g = 0.324 moles

Moles Cl = 23.6 g x 1 mole/35.5 g = 0.665 moles

Mole ratio Ca: Cl = 1 : 2

Empiracal formu = CaCl₂