J.R. S. answered 03/05/19
Ph.D. University Professor with 10+ years Tutoring Experience
HClO4 + NaOH ==> NaClO4 + H2O
moles of NaOH used = 0.02262 L x 0.0200 mol/L = 0.0004524 moles
moles HClO4 present = 0.0004524 moles NaOH x 1 mole HClO4/mole NaOH = 0.0004524 moles
concentration of HClO4 = 0.0004524 moles/0.02500 L = 0.018096 M = 0.01810 M