Chemistry problem 3

Question

At what temperature will 541 grams of water boil if 18.2 grams of glycerin (Molar mass= 92g/mol) are dissolved in it?

Answer 1

Glycerin is a non electrolyte so i = 1

ΔT = imK = (1)(18.2/92/0.541)(0.512) = boiling point elevation

Add bp elevation to 100C to get new bp