A spinner has 6 equally sized sections,6 are gray and 4 are blue. The spinner is spun twice. What’s the probability that the first spin lands on blue and the second spin lands on gray?
I assume you made a typo and the spinner has 10 equally sized sections, 6 are gray and 4 are blue.
The first and second spin are independent, so we can use the multiplication rule.
the probability that the first spin lands on blue = 6/10, because 6 of the 10 spots are blue
the probability that the second spin lands on gray = 4/10, because 4 of the 10 spots are gray
by the multiplication rule the probability of the first spin landing on blue and the second spin landing on gray equals 6/10 * 4/10 = 3/5 * 2/5 = 6/25
