Chemistry Help!

Question

Calculate the Ph of a solution made by 100 ml of .10 HCL and 100.0 ml of .050 M Nh4Cl

Answer 1

The hydrolysis of NH₄Cl, which is an acidic salt, will change the pH of the 0.1 M HCl by such a small amount, it can be neglected. NH₄Cl = NH₄⁺ + Cl^- and then NH₄⁺ + H₂O ==> NH₃ + H₃O⁺. You can find the [H₃O⁺] from the Ka for NH₄⁺ and using 0.050 M for NH₄Cl. It will be very small relative to the [HCl], and we shall neglect it.

Thus you are left with the pH of the 0.1 M HCl = -log 0.1 = 1 = pH

If you actually want to include the contribution of the NH₄Cl, repost the question stating that and I or someone else will assist you.