J.R. S. answered 03/04/19
Ph.D. University Professor with 10+ years Tutoring Experience
C2O42– + 2H2O ==> H2C2O4 + 2OH-
Look up Kb for oxalate (C2O4) and plug in to the equation
Kb = [x][2x]2/(0.1 M) and solve for x which will be the [OH-]
Find pOH and subtract from 14 to get pH