Louise K. answered 04/13/19
Former Teacher, Experienced Tutor, many subjects, especially math
This is a systems of equations problem. You have three variables:
Let W = weight of white chocolate package
Let M = weight of milk chocolate package
Let D = weight of dark chocolate package
Now create your three equations:
(A) 1W + 3M + 3D = 14
(B) 1W + 3M + 4D = 17
(C) 1W + 4M + 3D = 15
You do not even need to do all the algebra to figure out these equations. Look at equation A vs equation B. The only difference is an additional package of dark chocolate. The weight went from 14 to 17... so the difference in weight is 3 ounces. Therefore one package of dark chocolate weighs 3 ounces.
Likewise, look at the difference between equation A and equation C. The only difference is one added package of MILK chocolate. The weight has increased by 1 ounces for this additional package. Therefore one package of milk chocolate weighs 1 ounce.
Use the values for M = 2 and D = 3 to figure out the value for the white chocolate package, using any of the equations. If you use equation A, you will substitute and find:
(A) 1W + 3M + 3D = 14
W + 3(1) + 3(3) = 14
W + 3 + 9 = 14
W = 14 - 12
W = 2
Now plug these into B and C to check your answer! Always check your answer... it will save your grade.