what is an equation of the line perpendicular to y=-3x-5 that contains (-3,7)

Answer 1

First find the slope of the line. Since you are looking for a line perpendicular to y = -3x - 5, let's start finding the slope of that line. The slope is the number in front of the "x" if the line is in the y = mx + b format so its -3. Then, you must realize that a line perpendicular will have a slope that is the negative reciprocal of this, that is 1/3.

Next plug in that slope into the y = mx + b format, so y = 1/3x + b

Next plug in the point (-3, 7) into this equation, so 7 = 1/3(-3) + b and solve for b. In this case, b = 8.

Next plug in the b value you got into y = 1/3x + b to get the final equation, y = 1/3x + 8