what volume of hydrogen will be produced at STP by the reaction of 67.3 g of tin with excess water according to the following reaction

Answer 1

Sn + 2H2O ==> Sn(OH)2 + 2H2

67.3 g Sn x 1 mol/119 g x 2 mol H2/mol Sn x 22.4 L/mole = answer in liters