What mass of H2(g) is produced?

Question

An excess of aluminum foil is allowed to react with 225 mL of an aqueous solution of HCl (d=1.088 g/mL) that contains 18.0 % HCl by mass. What mass of H₂(g) is produced?

Answer 1

2Al + 6HCl ==> 2AlCl₃ + 3H₂

225 ml x 1.088 g/ml = g of HCl solution

g of HCl solution x 0.18 = g of HCl

g of HCl x molar mass HCl = moles HCl

moles HCl x 3 mol H₂/6 mol HCl x 2 g H₂/mol = mass H₂