J.R. S. answered 03/03/19
Ph.D. University Professor with 10+ years Tutoring Experience
(15ml)(0.016 M) = (100 ml)(x M) and x = 0.0024 M (2 sig figs)
10 ml x 1 L/1000 ml x 0.028 mol/L x 2 mol Cl-/mol CuCl2 = answer
Melissa W.
asked 03/03/19a) What is the concentration of the new, 100.0 mL solution prepared by diluting 15.0 mL of 0.016 M CuCl2?
b) How many moles of Cl1- are there in 10.0 mL of 0.028 M CuCl2 ?
J.R. S. answered 03/03/19
Ph.D. University Professor with 10+ years Tutoring Experience
(15ml)(0.016 M) = (100 ml)(x M) and x = 0.0024 M (2 sig figs)
10 ml x 1 L/1000 ml x 0.028 mol/L x 2 mol Cl-/mol CuCl2 = answer
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