The perimeter of a rectangle is 32 feet. The length is six more than the width. Find the length and width of the rectangle. This equation also requires to use substitution.

Answer 1

For rectangle, L + W + L + W = 2L + 2W

Given:

L = 6 + W

2L + 2W = P

2(W+6) + 2W = 32

4W + 12 = 32

4W = 20

W = 5

L = W + 6 = 11

Check:

Is 2(11) + 2(5) = 32 ?

32 = 32 ?yes

Answer 2

P = 2(L+W) => 32=2(L+W) => L+W = 16

L=W+6 => L-W = 6

Add the 2 equations to eliminate the W and find the value for L.

Use that value to to solve for W.