Metathesis reaction

Question

when 3.06 mL of 1.67-M ammonium Phosphate is mixed with 2.053 mL of 1.650-M ferrous acetate, a precipitate forms. Write balanced chemical equation a. Calculate the Theoretical Yield b, the limiting reactant c. calculate the grams of the reactant in excess (left over) after the reaction is complete

Answer 1

2(NH4)₃PO₄ + 3Fe(C2H3O2)2 => 6 NH₄C₂H₃O₂ + Fe₃(PO₄)₂ balanced equation

mmol ammonium phosphate = 3.06 ml x 1.67 mmol/ml = 5.11 mmol

mmol iron acetate = 2.053 ml x 1.65 mmol/ml = 3.39 mmol = LIMITING REACTANT

Theoretical yield = 3.39 mmol x 1 mmol iron phosphate/3 mmol iron acetate = mmoles

For yield in g or mg etc multiply by molar mass

To find g of ammonium phosphate left, use mole ratio of ammonium phosphate and iron acetate subtracting the iron acetate frm the ammonium phosphate and convert to grams using molar mass