The radius of a cylindrical gift box is (4x+1) inches. The height of the gift box is twice the radius. What is the surface area of the cylinder? Write your answer as a polynomial in standard form.

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The radius of a cylindrical gift box is ​(4x+1​) inches. The height of the gift box is twice the radius. What is the surface area of the​ cylinder? Write your answer as a polynomial in standard form.

Mark M. · Accepted Answer

r = 4x + 1h = 8x + 2SA = 2 areabase + areasurefaceSA = 2π(4x + 1)2 + 2π(4x + 1)(8x + 2)Can you simplify and answer?

The radius of a cylindrical gift box is (4x+1) inches. The height of the gift box is twice the radius. What is the surface area of the cylinder? Write your answer as a polynomial in standard form.

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The radius of a cylindrical gift box is ​(4x+1​) inches. The height of the gift box is twice the radius. What is the surface area of the​ cylinder? Write your answer as a polynomial in standard form.

1 Expert Answer

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

how to do I make a graph?

How do I know my answer?

how do you solve 8x+32/x^2-16

12p+15c>360

12p+15c>360

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The radius of a cylindrical gift box is (4x+1) inches. The height of the gift box is twice the radius. What is the surface area of the cylinder? Write your answer as a polynomial in standard form.