J.R. S. answered 02/26/19
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Ph.D. University Professor with 10+ years Tutoring Experience
PV = nRT
n = PV/RT = (1.56)(1.75)/(0.0821)(253) = moles
Ucy B.
asked 02/26/19How much gas is contained in a) 1.75 L at 253 K and 1.56 atm? Answer in units of mol.
J.R. S. answered 02/26/19
Ph.D. University Professor with 10+ years Tutoring Experience
PV = nRT
n = PV/RT = (1.56)(1.75)/(0.0821)(253) = moles
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