The cylinder volume is pi*R^2*H. Where. R = 4 inches, H = 6 inches
so, Volume = 301.6 in^3
The pan has an area of 9 x 11 = 99 in^2
Volume of the pan is h x 99. Where h is height of water in the pan,
Therefore; h x 99 = 301.59. Solving for h = 3.046 inches