Inactive Tutor answered 02/23/19
Tutor
New to Wyzant
y = 2^x
log_2(y) = x
ln y / ln 2 = x <--- change of base formula
ln y = x * ln 2
y = e^(x * ln 2) = (e^(x))^ln2
or
ln y = ln 2 * x
y = e^(ln2)^x
Maria H.
asked 02/23/19Inactive Tutor answered 02/23/19
y = 2^x
log_2(y) = x
ln y / ln 2 = x <--- change of base formula
ln y = x * ln 2
y = e^(x * ln 2) = (e^(x))^ln2
or
ln y = ln 2 * x
y = e^(ln2)^x
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