Given 134.8 grams of HCI, how many moles of MnCI2 will form?

Question

equation: MnO2+4HCI=CI2+MnCI2+2H2O

answer choices

a.343.08 moles

b.0.92 moles

c.118.32 moles

d.14.79 moles

Answer 1

MnO2 + 4HCI = => CI2 + MnCI2 + 2H2O ... balanced equation

moles HCl present = 134.8 g HCl x 36.5 g/mole = 3.693 moles HCl

moles MnCl2 formed = 3.693 moles HCl x 1 mole MnCl2/4 moles HCl = 0.92 moles (choice b)