How many grams of CuI2 are produced when 35 moles of Cu(NO3)2 react?

Question

equation: Cu(NO3)2+2KI=CuI2+2KNO3

Answer 1

Cu(NO3)2 + 2KI ==> CuI2 + 2KNO3 ... balanced equation

moles Cu(NO3)2 present = 35 moles

moles CuI2 produced = 35 moles Cu(NO3)2 x 1 mole CuI2/1 mole Cu(NO3)2 = 35 moles CuI2 produced

grams CuI2 produced = 35 moles x 317 g/mole = 11,095 g (11,000 g to 2 sig. figs.)