Dal J. answered • 11/07/14

Expert Instructor in Complex Subjects and Public Speaking

Okay, so first we'll set this up by common sense. We're going to assume that the solids in the tea have no effect on the heat, so 1 calorie will still raise/lower 1 ml of water (or tea) by 1 degree celcius. We're also, for convenience, going to remember that 1 g of ice melts to 1 g of water which has a volume of 1 ml. Ready to set this up?

We know the ice will ALL melt, so that's going to suck up 80*30 calories. We also have 30 grams of soon-to-be-unfrozen water at -10 degrees, for another 10*30 calories gone to take that water up to zero. Other than that, we have 190 ml at 86 degrees, for 190*86 = 16340 (positive) heat calories above zero celcius in the mix.

16340 -2400 -300 = 13640 calories above zero celcius left at equilibrium, in a cup containing 190+30 = 220 ml of tea.

13640/220= 62 degrees celcius.