
Frank M. answered 11/07/14
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Help With Emergencies and Understanding
This is a problem in specific heats of different materials. Let
- mw = the mass of the water & ms = the mass of the metal.
- cw = the specific heat of water, which is 4.18J/g * K & cs = the specific heat of the sample, which is unknown.
- The final temperature of the water = Tf.
- The initial temperature of the water = Ti. Then
- Since the temp of the water rises, the delta T for it is Tf - Ti, or 5 degrees Kelvin.
- Since the temp of the sample falls, its delta T is Ti - Tf, or (95 - 51.6) degrees Kelvin. Then
- mwcw(delta Tw) = mscs(delta Ts). Solve for cs to get the specific heat of the metal sample. Evaluate the expression left of the equal sign to obtain the quantity of heat transferred from the metal to the water.
- Additional hint: one ml of water weighs one gram.