Chemistry problem energy, I don't know where to start!

Question

A metal sample weighing 220. g is heated to 95.0 Celsius and then placed into 190. ml of water at 46.6 celcius. the final temperature of the water is 51.6 celcius. How much heat was transferred from the metal to the water? what is the specific heat of the metal? 

Answer 1

This is a problem in specific heats of different materials.  Let

1. m_w = the mass of the water & m_s = the mass of the metal.
2. c_w = the specific heat of water, which is 4.18J/g * K & c_s = the specific heat of the sample, which is unknown.
3. The final temperature of the water = T_f.
4. The initial temperature of the water = T_i.  Then
5. Since the temp of the water rises, the delta T for it is T_f - T_i, or 5 degrees Kelvin.
6. Since the temp of the sample falls, its delta T is T_i - T_f, or (95 - 51.6) degrees Kelvin.  Then
7. m_wc_w(delta T_w) = m_sc_s(delta T_s).  Solve for c_s to get the specific heat of the metal sample.  Evaluate the expression left of the equal sign to obtain the quantity of heat transferred from the metal to the water.
8. Additional hint:  one ml of water weighs one gram.