Polygon ABCD is translated to create polygon A′B′C′D′. Point A is located at (1, 5), and point A′ is located at (-2, 1). What is the distance from B to B′ ?

Question

Polygon ABCD is translated to create polygon A′B′C′D′. Point A is located at (1, 5), and point A′ is located at (-2, 1). What is the distance from B to B′ ?

Answer 1

The polygon is translated by <-2-1,1-5>=<-3,-4>

If B is at (x,y) then B’ is at (x-3,y-4)

D=sqrt((x₁-x₂)²+(y₁-y₂)²) =sqrt((x-(x-3))²+(y-(y-4))²) =sqrt(3²+4²) =sqrt(9+16) =sqrt(25) = 5

The distance is 5 units.