how do you write the equation of a line parallel to the given line & passing through the given point.?

Question

5= -10x+5y.   ( -2, 1 )

Answer 1

Hi Stephanie

 

First we put our equation into slope intercept form...

 

In slope intercept form, our equation is...

 

y = 2x + 1.

 

Now we use the formula, (y - y₁) = m (x - x₁).

 

(y - 1) = 2 ( x - (-2))  ---> (y - 1) = 2 (x + 2) ----> now distribute the 2 to the x and 2 inside the parentheses.

 

(y - 1) = 2x + 4 ---> next, add one to both sides of the equation...

 

y = 2x + 5.

 

Our equation y = 2x + 5 is the line parallel to the original equation and passes through the point (-2,1).